Question:
solve:y=root(a^2 b^2) . e^ax . cos(theta bx) ; dy/dx=
Answer:
Given, y = √(a2 + b2 ) * eax * cos(θ + bx)
Now, dy/dx = √(a2 + b2 ) *{a *eax * cos(θ + bx) - b*eax * sin(θ + bx) }
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